Q. 1

$3x = 7y$

$12y = 5x - 1$

$x = \frac{7y}{3}$

$12 y = 5(\frac{7y}{3}) - 1 12 y = \frac{35y}{3} - \frac{3}{3} 12 y = \frac{35y-3}{3} 36y = 35y - 3 y = -3 x = \frac{7(-3)}{3} x = \frac{-21}{3} x = -7 (-7, -3)$