Q. 4

y \, \alpha \, x^2 y = 1 \, when \, x = \frac{1}{2} y = kx^2 1 = k (\frac{1}{2})^2 1 = k (\frac{1}{4}) k = 1 \times 4 = 4 \Rightarrow y = 4x^2

  1. Find x when y = 9

    y = 4x^2 9 = 4x^2 x^2 = \frac{9}{4} x = \sqrt{\frac{9}{4}} x = \pm \frac{3}{2}