Q. 5

  1. y \, \alpha \, \sqrt{x} y = 12 when x = 36 y = k\sqrt{x} 12 = k \sqrt{36} k = \frac{12}{6} k = 2 \Rightarrow y = 2 \sqrt{x}

  2. Find x when y = 10

    y = 2 \sqrt{x} 10 = 2 \sqrt{x} \sqrt{x} = 10 \div 2 = 5 x = 5^2 x = 25